51. | _______ encoding has a transition at the beginning of each 0 bit. |
a. | RZ |
b. | Manchester |
c. | Differential Manchester |
d. | All the above |
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Answer: (c).Differential Manchester
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52. | PCM is an example of _______ conversion. |
a. | digital-to-digital |
b. | digital-to-analog |
c. | analog-to-analog |
d. | analog-to-digital |
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Answer: (d).analog-to-digital
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53. | If the frequency spectrum of a signal has a bandwidth of 500 Hz with the highest frequency at 600 Hz, what should be the sampling rate, according to the Nyquist theorem? |
a. | 200 samples/s |
b. | 500 samples/s |
c. | 1000 samples/s |
d. | 1200 samples/s |
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Answer: (d).1200 samples/s
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54. | The Nyquist theorem specifies the minimum sampling rate to be_______. |
a. | equal to the lowest frequency of a signal |
b. | equal to the highest frequency of a signal |
c. | twice the bandwidth of a signal |
d. | twice the highest frequency of a signal |
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Answer: (d).twice the highest frequency of a signal
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55. | Which of the following encoding methods does not provide for synchronization? |
a. | NRZ-L |
b. | RZ |
c. | NRZ-I |
d. | Manchester |
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Answer: (a).NRZ-L
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56. | Which encoding method uses alternating positive and negative values for 1s? |
a. | NRZ-I |
b. | RZ |
c. | Manchester |
d. | AMI |
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Answer: (d).AMI
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57. | Which quantization level results in a more faithful reproduction of the signal? |
a. | 2 |
b. | 8 |
c. | 16 |
d. | 32 |
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Answer: (d).32
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58. | Block coding can help in _______ at the receiver. |
a. | Synchronization |
b. | Error detection |
c. | Attenuation |
d. | both (a) and (b) |
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Answer: (d).both (a) and (b)
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59. | In _______ transmission, a start bit and a stop bit frame a character byte. |
a. | asynchronous serial |
b. | synchronous serial |
c. | parallel |
d. | (a) and (b) |
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Answer: (a).asynchronous serial
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60. | In asynchronous transmission, the gap time between bytes is _______. |
a. | fixed |
b. | variable |
c. | a function of the data rate |
d. | zero |
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Answer: (b).variable
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