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Welcome to the Network Layer MCQs Page

Dive deep into the fascinating world of Network Layer with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Network Layer, a crucial aspect of Networking. In this section, you will encounter a diverse range of MCQs that cover various aspects of Network Layer, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Networking.

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Check out the MCQs below to embark on an enriching journey through Network Layer. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Networking.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Network Layer. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Network Layer MCQs | Page 29 of 38

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Q281.
A packet has arrived in which the offset value is 100, the value of HLEN is 5 and the value of the total length field is 100. What is the number of the last byte

a.

880

b.

879

c.

881

d.

801

Discuss
Answer: (b).879
Q282.
Convert the following binary notation to hexadecimal notation –
10000000 00001011 00000011 00011111

a.

0x 80 0B 03 1E

b.

0x 81 0B 04 1E

c.

0x 80 0C 03 1F

d.

0x 80 0B 03 1F

Discuss
Answer: (d).0x 80 0B 03 1F
Q283.
Convert the following binary notation to dotted-decimal notation –
10000001 00001011 00001011 11101111

a.

129.11.11.239

b.

128.11.12.231

c.

127.11.13.244

d.

129.12.1.231

Discuss
Answer: (a).129.11.11.239
Q284.
Convert the following dotted-decimal notation to binary notation –
111.56.45.78

a.

01101111 00111000 00101101 01001110

b.

11101111 00111000 00101101 10001110

c.

10000000 00001011 00000011 00011111

d.

10000001 00001011 00001011 11101111

Discuss
Answer: (a).01101111 00111000 00101101 01001110
Q285.
What is the error (if any) in the following representation – 111.56.045.78?

a.

There should be no leading zeros

b.

We cannot have more than 4 bytes in an IPv4 address

c.

Each byte should be less than or equal to 255

d.

No error

Discuss
Answer: (a).There should be no leading zeros
Q286.
What is the error (if any) in the following representation – 221.34.7.8.20?

a.

There should be no leading zeros

b.

Each byte should be less than or equal to 255

c.

We cannot have more than 4 bytes in an IPv4 address

d.

No error

Discuss
Answer: (c).We cannot have more than 4 bytes in an IPv4 address
Q287.
What is the error (if any) in the following representation – 75.45.301.14?

a.

There should be no leading zeros

b.

We cannot have more than 4 bytes in an IPv4 address

c.

Each byte should be less than or equal to 255

d.

No error

Discuss
Answer: (c).Each byte should be less than or equal to 255
Q288.
What is the error (if any) in the following representation – 11100010.23.14.67?

a.

There should be no leading zeros

b.

We cannot have more than 4 bytes in an IPv4 address

c.

Each byte should be less than or equal to 255

d.

None of the mentioned

Discuss
Answer: (d).None of the mentioned
Q289.
The following IPv4 addresses in hexadecimal notation is – 10000001 00001011 00001011 11101111-

a.

0x810B0BEF

b.

0x810D0AFF

c.

0x810B0BFE

d.

0x810C0CEF

Discuss
Answer: (a).0x810B0BEF
Q290.
Find the number of addresses in a range if the first address is 146.102.29.0 and last address is 146.102.32.255.

a.

1028

b.

1024

c.

578

d.

512

Discuss
Answer: (b).1024
Page 29 of 38

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