Welcome to the Cost Estimation MCQs Page

Dive deep into the fascinating world of Cost Estimation with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Cost Estimation, a crucial aspect of Software Engineering. In this section, you will encounter a diverse range of MCQs that cover various aspects of Cost Estimation, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Software Engineering.

Check out the MCQs below to embark on an enriching journey through Cost Estimation. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Software Engineering.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Cost Estimation. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Cost Estimation MCQs | Page 7 of 15

Explore more Topics under Software Engineering

01

Basics

02

Software Life Cycle Models

03

Requirements Modeling

04

Software Design Concepts

05

Software Components

06

Quality Management

07

Software Metrics

08

Software Testing

09

Software Management

10

Risk Management

11

Software Reliability

12

Advanced Software Engineering

13

People Management and Team Organization

14

Project Planning and Control

15

Requirements Engineering

16

Modeling

17

Software Architecture

18

Software Maintenance

19

Software Tools

Q61.

What is the main advantage of using Function Point Analysis (FPA) over other cost estimation methods?

It is based on counting the number of different data structures used

It is particularly suitable for projects aimed at realizing business applications

It does not have any problems associated with determining the expected amount of code

All of the above

Discuss

Answer: (d).All of the above Explanation:FPA is a method of estimating costs that circumvents the problems associated with determining the expected amount of code. It is based on counting the number of different data structures used and is particularly suitable for projects aimed at realizing business applications where the structure of the data plays a dominant role.

Q62.

What is the purpose of applying corrections to reflect differences in complexity of the data types in FPA?

To improve the accuracy of the method

To simplify the method

To make the method less suitable for projects

To make the method more suitable for projects

Discuss

Answer: (a).To improve the accuracy of the method Explanation:In FPA, a further refinement is possible by applying corrections to reflect differences in complexity of the data types. This will help to improve the accuracy of the method by taking into account the complexity of each data type.

Q63.

What is the formula used to convert the total degree of influence to a technical complexity factor in FPA?

TCF = 0.65 + 0.01 * UFP

TCF = 0.65 + 0.01 * DI

TCF = 0.65 + 0.01 * FP

TCF = 0.65 + 0.01 * TCF

Discuss

Answer: (b).TCF = 0.65 + 0.01 * DI Explanation:The formula to convert the total degree of influence (DI) to a technical complexity factor (TCF) in FPA is TCF = 0.65 + 0.01 * DI.

Q64.

What is the unadjusted function point measure adjusted by in the FPA model?

The number of application characteristics

The degree of influence of each characteristic

The total degree of influence

The technical complexity factor

Discuss

Answer: (b).The degree of influence of each characteristic Explanation:The unadjusted function point measure is adjusted by taking into account a number of application characteristics that influence development effort. The degree of influence of each of these characteristics is valued on a six-point scale.

Q65.

How is the adjusted function point measure obtained in the FPA model?

FP=UFP x TCF

FP=UFP + TCF

FP=UFP/TCF

FP=UFP-TCF

Discuss

Answer: (a).FP=UFP x TCF Explanation:The (adjusted) function point measure FP is obtained through FP=UFP x TCF.

Q66.

How does the IFPUG help with counting function points in a uniform way in FPA?

By providing a list of data types and their counts

By providing guidelines on how to classify and count the various entities involved

By providing a direct mapping from function points to lines of code

By providing a formula to calculate the technical complexity factor

Discuss

Answer: (b).By providing guidelines on how to classify and count the various entities involved Explanation:The International Function Point User Group (IFPUG) has published extensive guidelines on how to classify and count the various entities involved. This should overcome many of the difficulties that analysts have in counting function points in a uniform way.

Q67.

What are some of the problems with FPA's handling of complexity?

It uses ordinal scales and counts complexity twice

It uses cardinal scales and counts complexity once

It uses nominal scales and counts complexity thrice

It uses interval scales and counts complexity four times

Discuss

Answer: (a).It uses ordinal scales and counts complexity twice Explanation:FPA distinguishes three levels of component complexity only. A component with 100 elements thus gets at most twice the number of function points of a component with one element. It has been suggested that a model which uses the raw complexity data, i.e. the number of data elements and file types referenced

Q68.

How is the degree of influence of each characteristic in the FPA model valued?

On a binary scale (yes/no)

On a ten-point scale

On a six-point scale

On a three-point scale

Discuss

Answer: (c).On a six-point scale Explanation:The degree of influence of each of these characteristics is valued on a six-point scale, ranging from zero (no influence, not present) to five (strong influence).

Q69.

What is the main purpose of COCOMO 2?

To provide a revision of the 1981 COCOMO model

To learn about significant changes in the software development industry

To offer a means to estimate costs for different types of projects

All of the above

Discuss

Answer: (d).All of the above Explanation:COCOMO 2 is a revision of the 1981 COCOMO model that has been tuned to the life cycle practices of the 1990s and 2000s. It reflects the experience and knowledge of cost estimation, and provides three increasingly detailed cost estimation models for different types of projects, as well as during different stages of a single project.

Q70.

What are the three models provided by COCOMO 2?

Application Composition model, Early Design model, and Post-Architecture model

Object Point model, Function Point model, and LOC model

High-level model, Medium-level model, and Low-level model

Waterfall model, Agile model, and Scrum model

Discuss

Answer: (a).Application Composition model, Early Design model, and Post-Architecture model Explanation:COCOMO 2 provides three increasingly detailed cost estimation models: the Application Composition model, mainly intended for prototyping efforts, the Early Design model, aimed at the architectural design stage, and the Post-Architecture model for the actual development stage of a software product.

Page 7 of 15

Welcome to the Cost Estimation MCQs Page

Cost Estimation MCQs | Page 7 of 15

Explore more Topics under Software Engineering

Basics

Software Life Cycle Models

Requirements Modeling

Software Design Concepts

Software Components

Quality Management

Software Metrics

Software Testing

Software Management

Risk Management

Software Reliability

Advanced Software Engineering

People Management and Team Organization

Project Planning and Control

Requirements Engineering

Modeling

Software Architecture

Software Maintenance

Software Tools

Suggested Topics

C Programming

Software Architecture and Design

Hadoop

MongoDB

Wireless and Mobile Communications

Digital Image Processing (DIP)

Software Engineering

Visual Basic

DBMS