| 91. | Data and instructions that are being used frequently are stored in |
| a. | Cache |
| b. | Block |
| c. | hard disk |
| d. | main memory |
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Answer: (b).Block
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| 92. | Processor-I/O involves data transferring between |
| a. | Computers |
| b. | Processor and I/O modules |
| c. | Registers |
| d. | User Processes |
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Answer: (b).Processor and I/O modules
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| 93. | Data register can be assigned to a |
| a. | Variety of Functions |
| b. | Variety of Devices |
| c. | Variety of Programs |
| d. | Variety of systems |
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Answer: (a).Variety of Functions
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| 94. | PerformanceX = 1/ Execution Time x the given relation shows that |
| a. | Performance is increased when execution time is decreased |
| b. | Performance is increased when execution time is increased |
| c. | Performance is decreased when execution time is decreased |
| d. | None |
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Answer: (a).Performance is increased when execution time is decreased
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| 95. | The processor having Clock cycle of 0.25ns will have the clock rate of |
| a. | 2GHz |
| b. | 3GHz |
| c. | 4GHz |
| d. | 8GHz |
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Answer: (c).4GHz
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| 96. | The valid and unimpeachable measurement of performance of any computer is |
| a. | Clock rate |
| b. | Instruction set |
| c. | Execution time |
| d. | Delay time |
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Answer: (c).Execution time
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| 97. | The native MIPS has the MIPS measurement of |
| a. | MIPS = Instruction count/(Execution time)10^6 |
| b. | MIPS = Instruction count/(Execution time)10^3 |
| c. | MIPS = Instruction count/Execution time |
| d. | MIPS = (Execution time)10^6 |
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Answer: (a).MIPS = Instruction count/(Execution time)10^6
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| 98. | If computer A execute a program in 10 seconds and computer B runs the same in 15 seconds, how much faster is computer A than computer B |
| a. | 1.4 times |
| b. | 1.5 times |
| c. | 1 time |
| d. | 5.1 times |
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Answer: (b).1.5 times
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| 99. | For two computers X and Y, if the performance of computer X is greater than the performance of computer Y, we have |
| a. | PerformanceX =2PerformanceX |
| b. | PerformanceX =PerformanceX |
| c. | PerformanceX < PerformanceY |
| d. | PerformanceX > PerformanceY |
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Answer: (d).PerformanceX > PerformanceY
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| 100. | The total amount of work done during execution, in a given time is referred to as |
| a. | Response time |
| b. | Execution time |
| c. | Through put |
| d. | Delay time |
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Answer: (c).Through put
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