Welcome to the Dynamic Programming MCQs Page
Dive deep into the fascinating world of Dynamic Programming with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Dynamic Programming, a crucial aspect of Data Structures and Algorithms. In this section, you will encounter a diverse range of MCQs that cover various aspects of Dynamic Programming, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Data Structures and Algorithms.
Check out the MCQs below to embark on an enriching journey through Dynamic Programming. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Data Structures and Algorithms.
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Dynamic Programming MCQs | Page 8 of 22
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Which of these arguments should be passed by the min_jumps function represented by the blanks?
#include<stdio.h>
#include<limits.h>
int min_jumps(int *arr, int strt, int end)
{
int idx;
if(strt == end)
return 0;
if(arr[strt] == 0) // jump cannot be made
return INT_MAX;
int min = INT_MAX;
for(idx = 1; idx <= arr[strt] && strt + idx <= end; idx++)
{
int jumps = min_jumps(____,____,____) + 1;
if(jumps < min)
min = jumps;
}
return min;
}
int main()
{
int arr[] ={1, 3, 5, 8, 9, 2, 6, 7, 6},len = 9;
int ans = min_jumps(arr, 0, len-1);
printf("%d\n",ans);
return 0;
}
#include<stdio.h>
#include<limits.h>
int min_jumps(int *arr, int strt, int end)
{
int idx;
if(strt == end)
return 0;
if(arr[strt] == 0) // jump cannot be made
return INT_MAX;
int min = INT_MAX;
for(idx = 1; idx <= arr[strt] && strt + idx <= end; idx++)
{
int jumps = min_jumps(arr, strt + idx, end) + 1;
if(jumps < min)
min = jumps;
}
return min;
}
int main()
{
int arr[] ={1, 2, 3, 4, 5, 4, 3, 2, 1},len = 9;
int ans = min_jumps(arr, 0, len-1);
printf("%d\n",ans);
return 0;
}
Which of the following “for” loops can be used instead of the inner for loop so that the output doesn’t change?
#include<stdio.h>
#include<limits.h>
int min_jump(int *arr, int len)
{
int j, idx, jumps[len];
jumps[len - 1] = 0;
for(idx = len - 2; idx >= 0; idx--)
{
int tmp_min = INT_MAX;
for(j = 1; j <= arr[idx] && idx + j < len; j++)
{
if(jumps[idx + j] + 1 < tmp_min)
tmp_min = jumps[idx + j] + 1;
}
jumps[idx] = tmp_min;
}
return jumps[0];
}
int main()
{
int arr[] ={1, 1, 1, 1, 1, 1, 1, 1, 1},len = 9;
int ans = min_jump(arr,len);
printf("%d\n",ans);
return 0;
}
#include<stdio.h>
#include<limits.h>
int min_jump(int *arr, int len)
{
int j, idx, jumps[len];
jumps[len - 1] = 0;
for(idx = len - 2; idx >= 0; idx--)
{
int tmp_min = INT_MAX;
for(j = 1; j <= arr[idx] && idx + j < len; j++)
{
if(jumps[idx + j] + 1 < tmp_min)
tmp_min = jumps[idx + j] + 1;
}
jumps[idx] = tmp_min;
}
return jumps[0];
}
int main()
{
int arr[] ={1, 1, 1, 1, 1, 1, 1, 1, 1},len = 9;
int ans = min_jump(arr,len);
printf("%d\n",ans);
return 0;
}
#include<stdio.h>
#include<limits.h>
int min_jump(int *arr, int len)
{
int j, idx, jumps[len];
jumps[len - 1] = 0;
for(idx = len - 2; idx >= 0; idx--)
{
int tmp_min = INT_MAX;
for(j = 1; j <= arr[idx] && idx + j < len; j++)
{
if(jumps[idx + j] + 1 < tmp_min)
tmp_min = jumps[idx + j] + 1;
}
jumps[idx] = tmp_min;
}
return jumps[0];
}
int main()
{
int arr[] ={9, 9, 9, 9, 9, 9, 9, 9, 9},len = 9;
int ans = min_jump(arr,len);
printf("%d\n",ans);
return 0;
}
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