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Welcome to the Dynamic Programming MCQs Page

Dive deep into the fascinating world of Dynamic Programming with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Dynamic Programming, a crucial aspect of Data Structures and Algorithms. In this section, you will encounter a diverse range of MCQs that cover various aspects of Dynamic Programming, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Data Structures and Algorithms.

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Check out the MCQs below to embark on an enriching journey through Dynamic Programming. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Data Structures and Algorithms.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Dynamic Programming. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Dynamic Programming MCQs | Page 12 of 22

Q111.
What is the time complexity of the brute force algorithm used to find the length of the longest palindromic subsequence?
Discuss
Answer: (b).O(2^n)
Q112.
For every non-empty string, the length of the longest palindromic subsequence is at least one.
Discuss
Answer: (a).True
Q113.
Longest palindromic subsequence is an example of ______________
Discuss
Answer: (b).2D dynamic programming
Q114.
Consider the following code. Which of the following lines completes the below code?
#include<stdio.h>
#include<string.h>
int max_num(int a, int b)
{
      if(a > b)
        return a;
      return b;
}
int lps(char *str1)
{
      int i,j,len;
      len = strlen(str1);
      char str2[len + 1];
      strcpy(str2, str1);
      ______________;
      int arr[len + 1][len + 1];
      for(i = 0; i <= len; i++)
          arr[i][0] = 0;
      for(i = 0; i <= len; i++)
          arr[0][i] = 0;
      for(i = 1; i <= len; i++)
      {
          for(j = 1; j <= len; j++)
          {
               if(str1[i-1] == str2[j - 1])
                   arr[i][j] = 1 + arr[i - 1][j - 1];
               else
                   arr[i][j] = max_num(arr[i - 1][j], arr[i][j - 1]);
          }
      }
      return arr[len][len];
}
int main()
{
     char str1[] = "ababcdabba";
     int ans = lps(str1);
     printf("%d",ans);
     return 0;
}

Discuss
Answer: (a).strrev(str2)
Q115.
What is the value stored in arr[3][3] when the following code is executed?
#include<stdio.h>
#include<string.h>
int max_num(int a, int b)
{
      if(a > b)
        return a;
      return b;
}
int lps(char *str1)
{
      int i,j,len;
      len = strlen(str1);
      char str2[len + 1];
      strcpy(str2, str1);
      strrev(str2);
      int arr[len + 1][len + 1];
      for(i = 0; i <= len; i++)
          arr[i][0] = 0;
      for(i = 0; i <= len; i++)
          arr[0][i] = 0;
      for(i = 1; i <= len; i++)
      {
          for(j = 1; j <= len; j++)
          {
                if(str1[i-1] == str2[j - 1])
                    arr[i][j] = 1 + arr[i - 1][j - 1];
                else
                    arr[i][j] = max_num(arr[i - 1][j], arr[i][j - 1]);
          }
      }
      return arr[len][len];
}
int main()
{
      char str1[] = "ababcdabba";
      int ans = lps(str1);
      printf("%d",ans);
      return 0;
}

a.

2

b.

3

c.

4

d.

5

Discuss
Answer: (a).2
Q116.
What is the output of the following code?
#include<stdio.h>
#include<string.h>
int max_num(int a, int b)
{
      if(a > b)
        return a;
      return b;
}
int lps(char *str1)
{
      int i,j,len;
      len = strlen(str1);
      char str2[len + 1];
      strcpy(str2, str1);
      strrev(str2);
      int arr[len + 1][len + 1];
      for(i = 0; i <= len; i++)
          arr[i][0] = 0;
      for(i = 0; i <= len; i++)
          arr[0][i] = 0;
      for(i = 1; i <= len; i++)
      {
          for(j = 1; j <= len; j++)
          {
               if(str1[i-1] == str2[j - 1])
                  arr[i][j] = 1 + arr[i - 1][j - 1];
               else
                  arr[i][j] = max_num(arr[i - 1][j], arr[i][j - 1]);
          }
      }
      return arr[len][len];
}
int main()
{
      char str1[] = "abcd";
      int ans = lps(str1);
      printf("%d",ans);
      return 0;
}
Discuss
Answer: (b).1
Q117.
What is the output of the following code?
#include<stdio.h>
#include<string.h>
int max_num(int a, int b)
{
      if(a > b)
        return a;
      return b;
}
int lps(char *str1)
{
      int i,j,len;
      len = strlen(str1);
      char str2[len + 1];
      strcpy(str2, str1);
      strrev(str2);
      int arr[len + 1][len + 1];
      for(i = 0; i <= len; i++)
          arr[i][0] = 0;
      for(i = 0; i <= len; i++)
          arr[0][i] = 0;
      for(i = 1; i <= len; i++)
      {
          for(j = 1; j <= len; j++)
          {
              if(str1[i-1] == str2[j - 1])
                  arr[i][j] = 1 + arr[i - 1][j - 1];
              else
                  arr[i][j] = max_num(arr[i - 1][j], arr[i][j - 1]);
          }
      }
      return arr[len][len];
}
int main()
{
      char str1[] = "abdgkagdjbccbba";
      int ans = lps(str1);
      printf("%d",ans);
      return 0;
}

a.

5

b.

7

c.

9

d.

11

Discuss
Answer: (c).9
Q118.
Which of the following methods can be used to solve the edit distance problem?
Discuss
Answer: (c).Both dynamic programming and recursion
Q119.
The edit distance satisfies the axioms of a metric when the costs are non-negative.
Discuss
Answer: (a).True
Q120.
Which of the following is an application of the edit distance problem?
Discuss
Answer: (d).All of the mentioned

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