Welcome to the Dynamic Programming MCQs Page
Dive deep into the fascinating world of Dynamic Programming with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Dynamic Programming, a crucial aspect of Data Structures and Algorithms. In this section, you will encounter a diverse range of MCQs that cover various aspects of Dynamic Programming, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Data Structures and Algorithms.
Check out the MCQs below to embark on an enriching journey through Dynamic Programming. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Data Structures and Algorithms.
Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Dynamic Programming. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!
Dynamic Programming MCQs | Page 7 of 22
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length price
1 2
2 5
3 6
4 9
5 9
6 17
7 17
8 18
9 20
10 22
Which of these pieces give the maximum price?
#include<stdio.h>
#include<limits.h>
int max_of_two(int a, int b)
{
if(a > b)
return a;
return b;
}
int rod_cut(int *prices, int len)
{
int max_price = INT_MIN; // INT_MIN is the min value an integer can take
int i;
if(len <= 0 )
return 0;
for(i = 0; i < len; i++)
max_price = max_of_two(_____________); // subtract 1 because index starts from 0
return max_price;
}
int main()
{
int prices[]={2, 5, 6, 9, 9, 17, 17, 18, 20, 22},len_of_rod = 10;
int ans = rod_cut(prices, len_of_rod);
printf("%d",ans);
return 0;
}
#include<stdio.h>
#include<limits.h>
int max_of_two(int a, int b)
{
if(a > b)
return a;
return b;
}
int rod_cut(int *prices, int len)
{
int max_price = INT_MIN; // INT_MIN is the min value an integer can take
int i;
if(len <= 0 )
return 0;
for(i = 0; i < len; i++)
max_price = max_of_two(prices[i] + rod_cut(prices,len - i - 1), max_price); // subtract 1 because index starts from 0
return max_price;
}
int main()
{
int prices[]={2, 5, 6, 9, 9, 17, 17, 18, 20, 22},len_of_rod = 3;
int ans = rod_cut(prices, len_of_rod);
printf("%d",ans);
return 0;
}
#include<stdio.h>
#include<limits.h>
int rod_cut(int *prices, int len)
{
int max_val[len + 1];
int i,j,tmp_price,tmp_idx;
max_val[0] = 0;
for(i = 1; i <= len; i++)
{
int tmp_max = INT_MIN; // minimum value an integer can hold
for(j = 1; j <= i; j++)
{
tmp_idx = i - j;
tmp_price = _____________; //subtract 1 because index of prices starts from 0
if(tmp_price > tmp_max)
tmp_max = tmp_price;
}
max_val[i] = tmp_max;
}
return max_val[len];
}
int main()
{
int prices[]={2, 5, 6, 9, 9, 17, 17, 18, 20, 22},len_of_rod = 5;
int ans = rod_cut(prices, len_of_rod);
printf("%d",ans);
return 0;
}
#include<stdio.h>
#include<limits.h>
int rod_cut(int *prices, int len)
{
int max_val[len + 1];
int i,j,tmp_price,tmp_idx;
max_val[0] = 0;
for(i = 1; i <= len; i++)
{
int tmp_max = INT_MIN; // minimum value an integer can hold
for(j = 1; j <= i; j++)
{
tmp_idx = i - j;
tmp_price = prices[j-1] + max_val[tmp_idx];//subtract 1 because index of prices starts from 0
if(tmp_price > tmp_max)
tmp_max = tmp_price;
}
max_val[i] = tmp_max;
}
return max_val[len];
}
int main()
{
int prices[]={2, 5, 6, 9, 9, 17, 17, 18, 20, 22},len_of_rod = 5;
int ans = rod_cut(prices, len_of_rod);
printf("%d",ans);
return 0;
}
#include<stdio.h>
#include<limits.h>
int rod_cut(int *prices, int len)
{
int max_val[len + 1];
int i,j,tmp_price,tmp_idx;
max_val[0] = 0;
for(i = 1; i <= len; i++)
{
int tmp_max = INT_MIN; // minimum value an integer can hold
for(j = 1; j <= i; j++)
{
tmp_idx = i - j;
tmp_price = prices[j-1] + max_val[tmp_idx];//subtract 1 because index of prices starts from 0
if(tmp_price > tmp_max)
tmp_max = tmp_price;
}
max_val[i] = tmp_max;
}
return max_val[len];
}
int main()
{
int prices[]={2, 5, 6, 9, 9, 17, 17, 18, 20, 22},len_of_rod = 5;
int ans = rod_cut(prices, len_of_rod);
printf("%d",ans);
return 0;
}
{1, 3, 5, 8, 9, 2, 6, 7, 6}
What is the minimum number of jumps required to reach the end of the array?
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