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Question

What will be the value stored in max_value when the following code is executed?
#include<stdio.h>
#include<limits.h>
int max_of_two(int a, int b)
{
       if(a > b)
         return a;
       return b;
}
int rod_cut(int *prices, int len)
{
       int max_price = INT_MIN; // INT_MIN is the min value an integer can take
       int i;
       if(len <= 0 )
          return 0;
       for(i = 0; i < len; i++)
          max_price = max_of_two(prices[i] + rod_cut(prices,len - i - 1), max_price); // subtract 1 because index starts from 0
       return max_price;
}
int main()
{
       int prices[]={2, 5, 6, 9, 9, 17, 17, 18, 20, 22},len_of_rod = 3;
       int ans = rod_cut(prices, len_of_rod);
       printf("%d",ans);
       return 0;
}

a.

5

b.

6

c.

7

d.

8

Answer: (c).7

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Q. What will be the value stored in max_value when the following code is executed?

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