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Welcome to the Microoperations MCQs Page

Dive deep into the fascinating world of Microoperations with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Microoperations, a crucial aspect of Computer Architecture. In this section, you will encounter a diverse range of MCQs that cover various aspects of Microoperations, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Computer Architecture.

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Check out the MCQs below to embark on an enriching journey through Microoperations. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Computer Architecture.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Microoperations. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Microoperations MCQs | Page 9 of 17

Discuss
Answer: (c).Assembly language compatible
Q82.
Negating the hexadecimal expression (eca8 6420)hex will give
Discuss
Answer: (a).1357 9bdfhex
Q83.
The program, that instigates a procedure while execution, is known as
Discuss
Answer: (a).Caller
Q84.
In the instruction addi $t0,$t0,4 , I is for adding
Discuss
Answer: (d).both a and b
Q85.
The data transfer instructions, that are used to transfer computer data from memory to
Discuss
Answer: (c).Register
Q86.
The representation of an instruction, in the form of fields is called
Discuss
Answer: (b).Instruction format
Q87.
Coping the parameter $a0 into $s2 will be written in assembly instruction as
Discuss
Answer: (b).move $s2, $a0
Q88.
Given instructions lw $t0,1200($t1); add $t0,$s2,$t0; sw $t0,1200($t1), are the compiled instruction of expression
Discuss
Answer: (c).A[300] = h + A[300]
Q89.
Code for writing byte from the destination can be written as
Discuss
Answer: (b).sb $t0,0($gp)
Q90.
The instruction, move $t0, $t1 describes
Discuss
Answer: (c).moving $t1 to $t0

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