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Welcome to the Linked Lists MCQs Page

Dive deep into the fascinating world of Linked Lists with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Linked Lists, a crucial aspect of Data Structures and Algorithms. In this section, you will encounter a diverse range of MCQs that cover various aspects of Linked Lists, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Data Structures and Algorithms.

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Check out the MCQs below to embark on an enriching journey through Linked Lists. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Data Structures and Algorithms.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Linked Lists. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Linked Lists MCQs | Page 16 of 17

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Q151.
Which of the following statements are true ?
i) practical application of XOR linked lists are in environments with limited space requirements, such as embedded devices.

ii)xor lists are not suitable because most garbage collectors will fail to work properly with classes or structures that don’t contain literal pointers

iii)in order to calculate the address of the next node you need to remember the address of the previous node

iv)xor lists are much efficient than single, doubly linked lists and arrays
Discuss
Answer: (b).i, ii, iii
Q152.
What’s wrong with this code which returns xor of two nodes address ?
//struct is common userdefined datatype in c/c++ and class is it's alternative
 
struct node* XOR (struct node *a, struct node *b) 
{
    return  ((int) (a) ^ (int) (b));   //this logic is used to fill the nodes with address of a xor linked list
}
Discuss
Answer: (b).type casting at return is missing
Q153.
Given 10,8,6,7,9
swap the above numbers such that finally you got 6,7,8,9,10

so now reverse 10

9,7,6,8,10

now reverse 9

8,6,7,9,10

7,6,8,9,10

6,7,8,9,10

At this point 6 is ahead so no more reversing can be done so stop.

To implement above algorithm which datastructure is better and why ?
Discuss
Answer: (c).xor linked list. because there is no overhead of pointers and so memory is saved
Discuss
Answer: (b).dynamic memory allocation
Discuss
Answer: (a).garbage collection and new or malloc operators respectively
Q156.
What datastructures can be used in implementing a free list?
Discuss
Answer: (b).linked list or sort trees
Discuss
Answer: (a).best fit, first fit, worst fit, simple-first fit
Discuss
Answer: (b).buddy allocation keeps several‭ ‬free lists,‭ ‬each one holds blocks which are of one particular size
Discuss
Answer: (c).certain blocks cannot be used if there are no pointers to them and hence they can be freed
Discuss
Answer: (d).both a and c are correct

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