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Welcome to the Breaking Protections MCQs Page

Dive deep into the fascinating world of Breaking Protections with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Breaking Protections, a crucial aspect of Reverse Engineering. In this section, you will encounter a diverse range of MCQs that cover various aspects of Breaking Protections, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Reverse Engineering.

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Check out the MCQs below to embark on an enriching journey through Breaking Protections. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Reverse Engineering.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Breaking Protections. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Breaking Protections MCQs | Page 3 of 7

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Q21.
What is the purpose of the Executable Modules window in OllyDbg?

a.

To show which DLLs are statically linked to the executable.

b.

To display the executable's usage message.

c.

To list all the functions within the executable.

d.

To show the assembly code for the executable.

Discuss
Answer: (a).To show which DLLs are statically linked to the executable. Explanation:The Executable Modules window in OllyDbg shows which DLLs are statically linked to the executable.
Q22.
What is the purpose of examining the thread creation code in Defender's initialization routine?

a.

To find out what code is being executed by the thread.

b.

To determine how NtCreateThread works.

c.

To learn about the CONTEXT data structure.

d.

To understand how to allocate stack space for a thread.

Discuss
Answer: (a).To find out what code is being executed by the thread. Explanation:The purpose of examining the thread creation code is to find out what code is being executed by the thread.
Q23.
What is brute-forcing?

a.

It's a method of decrypting codes.

b.

It's a method of generating encryption keys.

c.

It's a method of using all possible options to find a solution.

d.

It's a method of hacking into computers.

Discuss
Answer: (c).It's a method of using all possible options to find a solution. Explanation:Brute-forcing as letting the computer go through all possible keys until it finds one that properly decrypts the code.
Q24.
What does Defender use to generate its decryption key?

a.

The username and serial number information

b.

A single key readily available somewhere in the program

c.

A brute-force program

d.

The entire program is encrypted using a single key

Discuss
Answer: (a).The username and serial number information Explanation:Defender uses the username and serial number information to generate its decryption key.
Q25.
What is the advantage of Defender’s encryption approach?

a.

It prevents crackers from analyzing the entire program

b.

It makes it easier to write an unpacker program

c.

It encrypts the entire program using a single key

d.

It makes it easier to set breakpoints on the code

Discuss
Answer: (a).It prevents crackers from analyzing the entire program Explanation:The advantage of Defender’s encryption approach is that it prevents crackers from easily analyzing the entire program.
Q26.
What is the encryption algorithm used in Defender?

a.

CBC

b.

XOR

c.

RSA

d.

AES

Discuss
Answer: (a).CBC Explanation:Defender uses the Cipher Block Chaining (CBC) encryption algorithm.
Q27.
Why is it important for protection technologies to encrypt key code?

a.

To prevent crackers from elegantly loading the program in a disassembler such as IDA Pro and easily analyzing the entire program.

b.

To make it more difficult to set breakpoints on the code.

c.

To prevent automatic unpackers from decrypting the entire program.

d.

All of the above

Discuss
Answer: (d).All of the above Explanation:Encrypting key code prevents crackers from easily analyzing the entire program, makes it more difficult to set breakpoints on the code, and prevents automatic unpackers from decrypting the entire program.
Q28.
What is the main difference between a simple XOR algorithm and CBC?

a.

CBC uses a key to encrypt the plaintext, while a simple XOR algorithm does not use a key.

b.

CBC XORs each plaintext block with the previous encrypted block, while a simple XOR algorithm does not use previous encrypted blocks.

c.

CBC is highly vulnerable, while a simple XOR algorithm is quite secure.

d.

None of the above

Discuss
Answer: (b).CBC XORs each plaintext block with the previous encrypted block, while a simple XOR algorithm does not use previous encrypted blocks. Explanation:The main difference between a simple XOR algorithm and CBC is that CBC XORs each plaintext block with the previous encrypted block, while a simple XOR algorithm does not use previous encrypted blocks.
Q29.
Why is it difficult to hide the key from cracker’s eyes in copy protection technologies?

a.

Because eventually the key must be available to the program.

b.

Because crackers have special hardware to find the key.

c.

Because the key is encrypted in a way that makes it visible to crackers.

d.

None of the above

Discuss
Answer: (a).Because eventually the key must be available to the program. Explanation:It is difficult to hide the key from cracker’s eyes in copy protection technologies because eventually the key must be available to the program.
Q30.
What does Defender do before each function returns to the caller?

a.

It encrypts the entire program in memory

b.

It decrypts the entire program in memory

c.

It reencrypts each function

d.

It recompiles each function

Discuss
Answer: (c).It reencrypts each function Explanation:Defender reencrypts each function before that function returns to the caller.
Page 3 of 7

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