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Welcome to the The Computer MCQs Page

Dive deep into the fascinating world of The Computer with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of The Computer, a crucial aspect of Human Computer Interaction. In this section, you will encounter a diverse range of MCQs that cover various aspects of The Computer, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Human Computer Interaction.

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Check out the MCQs below to embark on an enriching journey through The Computer. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Human Computer Interaction.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of The Computer. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

The Computer MCQs | Page 22 of 26

Explore more Topics under Human Computer Interaction

Q211.
What are the two main kinds of technology used in disks?

a.

Magnetic disks and optical disks

b.

Floppy disks and hard disks

c.

Removable disks and fixed disks

d.

Recordable CDs and rewritable optical disks

Discuss
Answer: (a).Magnetic disks and optical disks Explanation:The two main kinds of technology used in disks are magnetic disks and optical disks. Magnetic disks, such as floppy disks and hard disks, use magnetic material to store information. Optical disks, such as CD-ROMs, use laser light to read and sometimes write information on the disk.
Q212.
What is the capacity of a typical floppy disk?

a.

300 kbytes

b.

1.4 Mbytes

c.

Several gigabytes (Gbytes)

d.

Several hundred kilobytes per second

Discuss
Answer: (b).1.4 Mbytes Explanation:A typical floppy disk has a capacity of 1.4 Mbytes (million bytes). However, it is important to note that floppy disks are removable, so you can have as many as you have room for on your desk.
Q213.
What is the access time that dominates random reads for hard disks?

a.

Several gigabytes (Gbytes)

b.

10 ms (milliseconds)

c.

Several hundred kilobytes per second

d.

650 megabytes

Discuss
Answer: (b).10 ms (milliseconds) Explanation:The access time that dominates random reads for hard disks is typically around 10 ms (milliseconds). This refers to the time taken to find the right track on the disk. Once the track is found, the transfer rate can be very high, reaching several hundred kilobytes per second.
Q214.
What is the capacity of a CD-ROM?

a.

Several gigabytes (Gbytes)

b.

300 kbytes

c.

1.4 Mbytes

d.

Around 650 megabytes

Discuss
Answer: (d).Around 650 megabytes Explanation:A CD-ROM has a capacity of around 650 megabytes. CD-ROMs are commonly used for published materials, such as online reference books, multimedia, and software distribution.
Q215.
What is the main advantage of optical media over magnetic disks?

a.

Faster access times

b.

Larger storage capacities

c.

Easier jukebox arrangement for online capacity

d.

More robust and durable

Discuss
Answer: (d).More robust and durable Explanation:The main advantage of optical media, such as CD-ROMs, over magnetic disks is that they are more robust and durable. Optical media are less prone to damage and can withstand rough handling compared to magnetic disks.
Q216.
What is the purpose of paging unused bits of programs out of RAM onto disk?

a.

To free up memory space

b.

To improve the logical functioning of programs

c.

To reduce disk space usage

d.

To increase interaction speed

Discuss
Answer: (a).To free up memory space Explanation:Paging unused bits of programs out of RAM onto disk is done to free up memory space. This allows the system to handle running multiple applications simultaneously without running out of memory.
Q217.
What is the main reason for delays due to swapping in the von Neumann bottleneck?

a.

Limited capacity of main memory

b.

Slow transfer rate of the disk

c.

Lack of information in the memory

d.

Excessive use of RAM

Discuss
Answer: (b).Slow transfer rate of the disk Explanation:Delays due to swapping in the von Neumann bottleneck are mainly caused by the slow transfer rate of the disk. The information needed is in the memory, but it takes time to transfer it between the disk and main memory, leading to delays in retrieving data.
Q218.
How can interactive system designers avoid some of the problems related to swapping?

a.

Increase the capacity of the disk

b.

Increase the transfer rate of the disk

c.

Use OCR to read documents instead of scanning as bitmaps

d.

Implement lazy information transfer and read in data during idle moments

Discuss
Answer: (d).Implement lazy information transfer and read in data during idle moments Explanation:Interactive system designers can avoid some of the problems related to swapping by implementing lazy information transfer. Instead of reading in the whole document at once, just enough information is read in for immediate display, and the rest is read during idle moments, reducing delays and improving user experience.
Q219.
What is one advantage of using compression techniques for text and bitmaps?

a.

It reduces the need for secondary storage devices

b.

It improves the transfer rate of the disk

c.

It enhances the quality of video images

d.

It reduces the amount of storage required

Discuss
Answer: (d).It reduces the amount of storage required Explanation:Compression techniques take advantage of the redundancy in text and bitmaps, allowing for a reduction in the amount of storage space needed to store them.
Q220.
How does run-length encoding compress bitmaps?

a.

By giving short codes to frequent words

b.

By representing long runs of the same value with length value pairs

c.

By computing the difference between successive frames

d.

By storing only the differences between successive frames

Discuss
Answer: (b).By representing long runs of the same value with length value pairs Explanation:Run-length encoding compresses bitmaps by representing long runs of the same value with length value pairs. For example, a sequence of repeated white pixels could be represented as "10 white pixels" instead of storing each individual white pixel separately.
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