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Welcome to the Stacks and Queues MCQs Page

Dive deep into the fascinating world of Stacks and Queues with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Stacks and Queues, a crucial aspect of Data Structures and Algorithms. In this section, you will encounter a diverse range of MCQs that cover various aspects of Stacks and Queues, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Data Structures and Algorithms.

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Check out the MCQs below to embark on an enriching journey through Stacks and Queues. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Data Structures and Algorithms.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Stacks and Queues. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Stacks and Queues MCQs | Page 22 of 25

Q211.
The essential condition which is checked before insertion in a linked queue is?
Discuss
Answer: (b).Overflow
Q212.
The essential condition which is checked before deletion in a linked queue is?
Discuss
Answer: (a).Underflow
Q213.
With what data structure can a priority queue be implemented?
Discuss
Answer: (d).All of the mentioned
Q214.
Which of the following is not an application of priority queue?
Discuss
Answer: (c).Undo operation in text editors
Q215.
Select the appropriate code that inserts elements into the list based on the given key value.
(head and trail are dummy nodes to mark the end and beginning of the list, they do not contain any priority or element)
a)

public void insert_key(int key,Object item) 
{
 if(key<0)
 {
  Systerm.our.println("invalid");
  System.exit(0);
 }
 else
 {
  Node temp = new Node(key,item,null);
  if(count == 0)
  {
   head.setNext(temp);
   temp.setNext(trail);
  }
  else
  {
   Node dup = head.getNext();
   Node cur = head;
   while((key>dup.getKey()) && (dup!=trail))
   {
    dup = dup.getNext();
    cur = cur.getNext();
   }
   cur.setNext(temp);
   temp.setNext(dup);
  }
  count++;
 }
}

b)

public void insert_key(int key,Object item) 
{
 if(key<0)
 {
  Systerm.our.println("invalid");
  System.exit(0);
 }
 else
 {
  Node temp = new Node(key,item,null);
  if(count == 0)
  {
   head.setNext(temp);
   temp.setNext(trail);
  }
  else
  {
   Node dup = head.getNext();
   Node cur = dup;
   while((key>dup.getKey()) && (dup!=trail))
   {
    dup = dup.getNext();
    cur = cur.getNext();
   }
   cur.setNext(temp);
   temp.setNext(dup);
  }
  count++;
 }
}

c)

public void insert_key(int key,Object item) 
{
 if(key<0)
 {
  Systerm.our.println("invalid");
  System.exit(0);
 }
 else
 {
  Node temp = new Node(key,item,null);
  if(count == 0)
  {
   head.setNext(temp);
   temp.setNext(trail);
  }
  else
  {
   Node dup = head.getNext();
   Node cur = head;
   while((key>dup.getKey()) && (dup!=trail))
   {
    dup = dup.getNext();
    cur = cur.getNext();
   }
   cur.setNext(dup);
   temp.setNext(cur);
  }
  count++;
 }
}

d) None of the mentioned

a.

a

b.

b

c.

c

d.

d

Discuss
Answer: (a).a
Q216.
What is the time complexity to insert a node based on key in a priority queue?
Discuss
Answer: (c).O(n)
Q217.
What is the functionality of the following piece of code?
public Object delete_key() 
{
 if(count == 0)
 {
  System.out.println("Q is empty");
  System.exit(0);
 }
 else
 {
  Node cur = head.getNext();
  Node dup = cur.getNext();
  Object e = cur.getEle();
  head.setNext(dup);
  count--;
  return e;
 }
}
Discuss
Answer: (c).Delete the first element in the list
Discuss
Answer: (c).Interrupt handling
Discuss
Answer: (d).All of the mentioned
Q220.
What is the time complexity to insert a node based on position in a priority queue?
Discuss
Answer: (c).O(n)

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