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Welcome to the Public Key Cryptography and RSA MCQs Page

Dive deep into the fascinating world of Public Key Cryptography and RSA with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Public Key Cryptography and RSA, a crucial aspect of Cryptography and Network Security. In this section, you will encounter a diverse range of MCQs that cover various aspects of Public Key Cryptography and RSA, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Cryptography and Network Security.

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Check out the MCQs below to embark on an enriching journey through Public Key Cryptography and RSA. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Cryptography and Network Security.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Public Key Cryptography and RSA. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Public Key Cryptography and RSA MCQs | Page 2 of 4

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Q11.
For the Knapsack: {1 6 8 15 24}, find the plain text code if the ciphertext is 38.
Discuss
Answer: (b).01101
Q12.
Set {1, 2, 3, 9, 10, and 24} is superincreasing.
Discuss
Answer: (b).False
Q13.
A superincreasing knapsack problem is ____ to solve than a jumbled knapsack.
Discuss
Answer: (a).Easier
Q14.
Consider knapsack that weighs 23 that has been made from the weights of the superincreasing series {1, 2, 4, 9, 20, and 38}. Find the โ€˜nโ€™.
Discuss
Answer: (b).010011
Q15.
Another name for Merkle-Hellman Cryptosystem is
Discuss
Answer: (b).Knapsack
Q16.
In Merkle-Hellman Cryptosystem, the hard knapsack becomes the private key and the easy knapsack becomes the public key.
Discuss
Answer: (b).False
Q17.
In Merkle-Hellman Cryptosystem, the public key can be used to decrypt messages, but cannot be used to decrypt messages. The private key encrypts the messages.
Discuss
Answer: (b).False
Q18.
The plaintext message consist of single letters with 5-bit numerical equivalents from (00000)2 to (11001)2. The secret deciphering key is the superincreasing 5-tuple (2, 3, 7, 15, 31), m = 61 and a = 17. Find the ciphertext for the message โ€œWHYโ€.
Discuss
Answer: (a).C= (148, 143, 50)
Q19.
For p = 11 and q = 17 and choose e=7. Apply RSA algorithm where PT message=88 and thus find the CT.
Discuss
Answer: (c).11
Q20.
For p = 11 and q = 17 and choose e=7. Apply RSA algorithm where Cipher message=11 and thus find the plain text.
Discuss
Answer: (a).88
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