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Welcome to the Cryptographic Hash Functions MCQs Page

Dive deep into the fascinating world of Cryptographic Hash Functions with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Cryptographic Hash Functions, a crucial aspect of Cryptography and Network Security. In this section, you will encounter a diverse range of MCQs that cover various aspects of Cryptographic Hash Functions, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Cryptography and Network Security.

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Check out the MCQs below to embark on an enriching journey through Cryptographic Hash Functions. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Cryptography and Network Security.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Cryptographic Hash Functions. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Cryptographic Hash Functions MCQs | Page 1 of 8

Q1.
In Singular elliptic curve, the equation x^3+ax+b=0 does ____ roots.
Discuss
Answer: (a).does not have three distinct
Q2.
How many real and imaginary roots does the equation y^2=x^3-1 have
Discuss
Answer: (d).2 imaginary, 1 real
Q3.
How many real and imaginary roots does the equation y^2=x^3-4x have
Discuss
Answer: (b).all real
Q4.
In the elliptic curve group defined by y^2= x^3- 17x + 16 over real numbers, what is P + Q if P = (0,-4) and Q = (1, 0)?
Discuss
Answer: (a).(15, -56)
Q5.
In the elliptic curve group defined by y^2= x^3- 17x + 16 over real numbers, what is 2P if P = (4, 3.464)?
Discuss
Answer: (a).(12.022, -39.362)
Q6.
“Elliptic curve cryptography follows the associative property.”
Discuss
Answer: (a).True
Q7.
“In ECC, the inverse of point P =(x1, y1) is Q = (-x1, y1). “
Discuss
Answer: (b).False
Q8.
On adding the two points P (4,2) and Q (10, 6) in the elliptic curve E11(1,1) we get
Discuss
Answer: (b).(6,4)
Q9.
If P = (1,4) in the elliptic curve E13(1, 1) , then 4P is
Discuss
Answer: (d).(8, 1)
Q10.
Multiply the point P=(8, 1) by a constant 3, thus find 3P, in the elliptic curve E13(1, 1)
Discuss
Answer: (a).(10,7)
Page 1 of 8

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