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Welcome to the Understanding Compiled Arithmetic MCQs Page

Dive deep into the fascinating world of Understanding Compiled Arithmetic with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Understanding Compiled Arithmetic, a crucial aspect of Reverse Engineering. In this section, you will encounter a diverse range of MCQs that cover various aspects of Understanding Compiled Arithmetic, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Reverse Engineering.

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Check out the MCQs below to embark on an enriching journey through Understanding Compiled Arithmetic. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Reverse Engineering.

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Understanding Compiled Arithmetic MCQs | Page 5 of 7

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Q41.
Why is the last digit in each reciprocal incremented by one?

a.

To make the result more accurate

b.

To make the multiplication faster

c.

To make the division more accurate

d.

None of the above

Discuss
Answer: (a).To make the result more accurate Explanation:The last digit in each reciprocal is incremented by one to round the fraction upward to obtain an accurate integer result within the given bits.
Q42.
When do compilers use reciprocal in multiplication instructions?

a.

When the divisor is a power of 2

b.

When the dividend is a power of 2

c.

When both the dividend and divisor are powers of 2

d.

None of the above

Discuss
Answer: (d).None of the above Explanation:Compilers use reciprocal in multiplication instructions when the divisor is not a power of 2.
Q43.
What is modulo?

a.

Division with different result

b.

The same as division

c.

Multiplication with different result

d.

Subtraction with different result

Discuss
Answer: (a).Division with different result Explanation:Modulo is the same operation as division, except that you take a different part of the result.
Q44.
What is the most common and intuitive method for calculating the modulo of a signed 32-bit integer?

a.

Division using IDIV instruction

b.

Subtraction using SUB instruction

c.

Multiplication using MUL instruction

d.

Addition using ADD instruction

Discuss
Answer: (a).Division using IDIV instruction Explanation:The most common and intuitive method for calculating the modulo of a signed 32-bit integer is by dividing the two values using IDIV, the processor’s signed division instruction.
Q45.
Why is the approach of using IDIV not the fastest in terms of runtime performance?

a.

Because IDIV is a fairly slow instruction

b.

Because IDIV is a fast instruction

c.

Because there is an error in the implementation

d.

Because it is not supported by the processor

Discuss
Answer: (a).Because IDIV is a fairly slow instruction Explanation:IDIV is a fairly slow instruction, one of the slowest in the entire instruction set.
Q46.
What do some compilers use in order to determine the modulo?

a.

Division using IDIV instruction

b.

Subtraction using SUB instruction

c.

Multiplication using MUL instruction

d.

Multiplication by a reciprocal

Discuss
Answer: (d).Multiplication by a reciprocal Explanation:Some compilers actually use a multiplication by a reciprocal in order to determine the modulo.
Q47.
Why do modern 32-bit software use larger-than-32-bit integer data types?

a.

For high-precision timers.

b.

For high-precision signal processing.

c.

Both a and b

d.

None of the above

Discuss
Answer: (c).Both a and b Explanation:Modern 32-bit software use larger-than-32-bit integer data types for various purposes such as high-precision timers, high-precision signal processing, and many others.
Q48.
How does the compiler perform arithmetic operations on 64-bit data types?

a.

By using specialized sequences to perform arithmetic operations on them.

b.

By representing full operands as several 32-bit integers.

c.

By using advanced processor enhancements such as SSE, SSE2, and SSE3.

d.

Both a and b

Discuss
Answer: (d).Both a and b Explanation:When working with integers larger than 32-bits, the compiler employs several 32-bit integers to represent the full operands. In these cases arithmetic can be performed in different ways, depending on the specific compiler. The compiler combines two 32-bit integers and uses specialized sequences to perform arithmetic operations on them.
Q49.
Do all compilers have built-in mechanisms for dealing with 64-bit data types?

a.

Yes, all compilers have built-in mechanisms.

b.

No, only modern compilers provide built-in support for 64-bit data types.

c.

No, some compilers might treat 64-bit data types as data structures containing several integers.

d.

Both b and c

Discuss
Answer: (d).Both b and c Explanation:Most modern compilers provide built-in support for 64-bit data types. These data types are usually stored as two 32-bit integers in memory, and the compiler generates special code when arithmetic operations are performed on them. However, other compilers might treat these data types as data structures containing several integers, requiring the program or a library to provide specific code that performs arithmetic operations on these data types.
Q50.
How are 64-bit data types usually stored in memory?

a.

As a single 64-bit integer.

b.

As two 16-bit integers.

c.

As two 32-bit integers.

d.

As four 8-bit integers.

Discuss
Answer: (c).As two 32-bit integers. Explanation:64-bit data types are usually stored as two 32-bit integers in memory.
Page 5 of 7

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