adplus-dvertising
frame-decoration

Question

Why is the approach of using IDIV not the fastest in terms of runtime performance?

a.

Because IDIV is a fairly slow instruction

b.

Because IDIV is a fast instruction

c.

Because there is an error in the implementation

d.

Because it is not supported by the processor

Posted under Reverse Engineering

Answer: (a).Because IDIV is a fairly slow instruction Explanation:IDIV is a fairly slow instruction, one of the slowest in the entire instruction set.

Engage with the Community - Add Your Comment

Confused About the Answer? Ask for Details Here.

Know the Explanation? Add it Here.

Q. Why is the approach of using IDIV not the fastest in terms of runtime performance?

Similar Questions

Discover Related MCQs

Q. What do some compilers use in order to determine the modulo?

Q. Why do modern 32-bit software use larger-than-32-bit integer data types?

Q. How does the compiler perform arithmetic operations on 64-bit data types?

Q. Do all compilers have built-in mechanisms for dealing with 64-bit data types?

Q. How are 64-bit data types usually stored in memory?

Q. How are 64-bit integers usually added?

Q. What is the difference between the ADD and ADC instructions?

Q. Which parts of the operands are added using the regular ADD instruction?

Q. How are the upper 32 bits of the operands added?

Q. What is the purpose of type casting in programs?

Q. Which instruction is used to increase the size of an unsigned integer?

Q. What happens during zero extending?

Q. Which operands are supported by MOVZX instruction for conversion?

Q. What is sign extending used for?

Q. What is the purpose of type conversions in programming?

Q. What instruction is used to increase the size of an unsigned integer?

Q. What is sign extending?

Q. Which instruction is used to perform sign extending when enlarging an integer?

Q. What is the purpose of the CDQ instruction?

Q. What is the LEA instruction used for?