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Welcome to the Deciphering Code Structures MCQs Page

Dive deep into the fascinating world of Deciphering Code Structures with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Deciphering Code Structures, a crucial aspect of Reverse Engineering. In this section, you will encounter a diverse range of MCQs that cover various aspects of Deciphering Code Structures, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Reverse Engineering.

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Check out the MCQs below to embark on an enriching journey through Deciphering Code Structures. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Reverse Engineering.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Deciphering Code Structures. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Deciphering Code Structures MCQs | Page 9 of 11

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Answer: (b).A for loop skips the counter increment when a loop skip-cycle statement is used, while a while loop does not skip the counter increment Explanation:In a for loop, the code that increments the counter is considered part of the loop's logical statement, which is why a loop skip-cycle statement does not skip the counter increment in such loops. In a while loop, the counter is typically incremented inside the conditional statement using the ++ operator, so a loop skip-cycle statement does not skip the counter increment in such loops.
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Answer: (b).A restructuring of high-level code aimed at producing more efficient machine code Explanation:Loop unrolling is a code-shaping level optimization that is essentially a restructuring of high-level code aimed at producing more efficient machine code.
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Answer: (d).It reduces the loop’s overhead Explanation:Loop unrolling is more efficient because it reduces the loop’s overhead, which means that the CMP and JL instructions will be executed fewer times.
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Answer: (a).Eliminating the loop altogether Explanation:The more aggressive type of loop unrolling is to eliminate the loop altogether and actually duplicate its body as many times as needed.
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Answer: (a).To reduce the number of conditional jumps required for implementing a given logical statement. Explanation:The main goal of branchless logic optimization is to eliminate or at least reduce the number of conditional jumps required for implementing a given logical statement. This is done to improve the performance of the code by minimizing the number of times the processor has to refill its pipeline due to incorrect branch predictions.
Q86.
What are the two major types of branchless logic code emitted by popular compilers?
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Answer: (a).Arithmetic-based and conditional-based Explanation:The two major types of branchless logic code emitted by popular compilers are arithmetic-based and conditional-based. The arithmetic-based approach converts logic into a purely arithmetic sequence that provides the same end result as the original high-level language logic. The conditional-based approach employs special conditional instructions (when available on the target CPU) to eliminate or reduce the number of jumps required in order to implement logic.
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Answer: (b).They are too slow and can cause performance issues. Explanation:The use of conditional jumps in pipelined CPUs can cause performance issues because the processor must guess or predict whether the jump will take place or not and based on that guess decide which instructions to add to the end of the pipeline. If it guesses wrong, the entire pipeline is emptied and must be refilled, which is a highly expensive operation.
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Answer: (a).It reduces the amount of time wasted in refilling the pipeline Explanation:When a processor encounters a conditional jump, it must guess or predict whether the jump will take place or not, and based on that guess decide which instructions to add to the end of the pipeline. If it guesses wrong, the entire pipeline is emptied and must be refilled. The amount of time wasted in these situations heavily depends on the processor’s internal design and primarily on its pipeline length, but in most pipelined CPUs refilling the pipeline is a highly expensive operation.
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Answer: (c).To execute special instructions only if certain conditions exist Explanation:Conditional instructions are used by compilers to execute special instructions only if certain conditions exist. If the conditions are not met, the processor will simply ignore the instruction and move on.
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Answer: (b).SETcc stores the logic test result in an operand, while Jcc performs a jump Explanation:SETcc is a set of instructions that perform the same logical flag tests as the conditional jump instructions (Jcc), except that instead of performing a jump, the logic test is performed, and the result is stored in an operand.

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