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Welcome to the Deciphering Code Structures MCQs Page

Dive deep into the fascinating world of Deciphering Code Structures with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Deciphering Code Structures, a crucial aspect of Reverse Engineering. In this section, you will encounter a diverse range of MCQs that cover various aspects of Deciphering Code Structures, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Reverse Engineering.

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Check out the MCQs below to embark on an enriching journey through Deciphering Code Structures. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Reverse Engineering.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Deciphering Code Structures. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Deciphering Code Structures MCQs | Page 7 of 11

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Answer: (b).Repeatedly dividing the items into smaller groups Explanation:The process is repeated for each of the smaller groups until the individual items are reached.
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Answer: (c).The binary search implementation represents the switch block as a tree Explanation:The binary search implementation represents the switch block as a tree, while the table implementation uses a table lookup operation.
Q63.
What does the compiler do when the provided value is not found in a binary search implementation for switch blocks?
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Answer: (b).It exits the conditional block Explanation:The process continues until the correct item is found or until the conditional block is exited if no case block is found for the value being searched.
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Answer: (a).They involve numerous subtractions on a single register. Explanation:Tree-based n-way conditionals involve numerous subtractions on a single register, making them easier to identify in disassembled code.
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Answer: (b).It divides the searchable items into two equally sized groups based on their values and records the range of values contained in each group. Explanation:A binary tree search involves dividing the searchable items into two equally sized groups based on their values and recording the range of values contained in each group. The process is then repeated for each of the smaller groups until the individual items are reached.
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Answer: (b).By subtracting certain values from the original value passed to the conditional block, constantly checking if the result is zero. Explanation:The compiler typically starts with the original value passed to the conditional block and gradually subtracts certain values from it (these are usually the case block values), constantly checking if the result is zero. This is simply an efficient way to determine which case block to jump into using the smallest possible code.
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Answer: (a).Pretested loops contain the loop body followed by the logic, while posttested loops contain logic followed by the loop body. Explanation:Pretested loops contain logic followed by the loopโ€™s body, while posttested loops contain the loop body followed by the logic.
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Answer: (b).Loops that test the counter before the loop executes Explanation:Pretested loops are loops that test the counter before the loop executes.
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Answer: (a).Because they have two jump instructions Explanation:Pretested loops are less efficient than posttested ones because they have two jump instructions.
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Answer: (c).The loop body will use an incorrect value for accessing an array Explanation:The potential risk of using a pretested loop with an out-of-bounds counter value is that the loop body will use an incorrect value for accessing an array.

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