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Question

What will be the output of the following R code? 
> set.seed(20)
> x <- rnorm(100)
> e <- rnorm(100, 0, 2)
> y <- 0.5 + 2 * x + e 
> summary(y)

a.

Min. 1st Qu. Median Mean 3rd Qu. Max.
-6.4080 -1.5400 0.6789 0.6893 2.9300 6.5050

b.

Min. 1st Qu. Median Mean 3rd Qu. Max.
-6.4080 -10.5400 0.6789 5.6893 2.9300 6.5050

c.

Min. 1st Qu. Median Mean 3rd Qu. Max.
-1.4080 -6.5400 0.6789 0.6893 2.9300 6.5050

d.

Error

Posted under Profiling,Simulation and Data Analysis R Programming

Answer: (a).Min. 1st Qu. Median Mean 3rd Qu. Max.
-6.4080 -1.5400 0.6789 0.6893 2.9300 6.5050

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