adplus-dvertising
frame-decoration

Question

Adding 1 and 1 in modulo-2 arithmetic results in _________.

a.

1

b.

2

c.

0

d.

none of the above

Posted under Networking

Answer: (c).0

Engage with the Community - Add Your Comment

Confused About the Answer? Ask for Details Here.

Know the Explanation? Add it Here.

Q. Adding 1 and 1 in modulo-2 arithmetic results in _________.

Similar Questions

Discover Related MCQs

Q. In block coding, if k =2 and n =3, we have _______ invalid codewords.

Q. The Hamming distance between equal codewords is _________.

Q. The Hamming distance between 100 and 001 is ________.

Q. In block coding, if n = 5, the maximum Hamming distance between two codewords is ________.

Q. If the Hamming distance between a dataword and the corresponding codeword is three, there are _____ bits in error.

Q. The _______ of a polynomial is the highest power in the polynomial.

Q. The divisor in a cyclic code is normally called the _________.

Q. A generator that contains a factor of ____ can detect all odd-numbered errors.

Q. Checksums use _________ arithmetic.

Q. In one's complement arithmetic, if positive 7 is 0111, then negative 7 is ________.

Q. The checksum of 1111 and 1111 is _________.

Q. The checksum of 0000 and 0000 is __________.

Q. In a Go-Back-N ARQ, if the window size is 63, what is the range of sequence numbers?

Q. In Go-Back-N ARQ, if frames 4, 5, and 6 are received successfully, the receiver may send an ACK _______ to the sender.

Q. ARQ stands for _______.

Q. For Stop-and-Wait ARQ, for 10 data packets sent, _______ acknowledgments are needed.

Q. HDLC is an acronym for _______.

Q. Data link control deals with the design and procedures for ______ communication.

Q. _______ in the data link layer separates a message from one source to a destination, or from other messages going from other sources to other destinations.

Q. In _______ framing, there is no need for defining the boundaries of frames.