Q. Match the following :
a. TTL                          1. High fan out
b. ECL                         2. Low propagation delay
c. CMOS                     3. High power dissipation

Code : a b c

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Q. Identify the operation which is commutative but not associative ?

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Q. Extremely low power dissipation and low cost per gate can be achieved in:

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Q. An example of a universal building block is

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Q. The dual of a Boolean expression is obtained by interchanging

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Q. Given that (292)10 = (1204)x in some number system x. The base x of that number system is

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Q. The sum of products, expansion for the function
F(x, y, z) = (x, + y) z' is given as

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Q. The BCD adder to add two decimal digits needs minimum of

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Q. The Excess-3 decimal code is a self-complementing code because

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Q. The equivalent hexadecimal notation for octal number 2550276 is :

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Q. A byte addressable computer has a memory capacity of 2m Kbytes and can perform 2n operations. An instruction involving 3 operands and one operator needs a maximum of

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Q. One of the main features that distinguish microprocessor from micro-computers is

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Q. Consider a code with five valid code words of length ten :
0000000000, 0000011111, 1111100000, 1110000011, 1111111111
Hamming distance of the code is

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Q. Which of the following logic expressions is incorrect ?

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Q. The IEEE-754 double precision format to represent floating point numbers, has a length of _____ bits.

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Q. The Simplified form of a Boolean equation for the following truth table is

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Q. The Simplified form of a Boolean equation (AB'+AB'C+Ac)(A'C' +B') is

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Q. In a Positive edge triggered JK flip-flop, if J and K both are high then the output will be _______ on the rising edge of the clock.

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Q. ECL is the fastest of all logic families. High Speed in ECL is possible because transistors are used in difference amplifier configuration, in which they are never driven into __________.

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Q. A binary 3-bit down counter uses J-K flip-flops, FFi with inputs Ji, Ki and outputs Qi, i=0,1,2 respectively. The minimized expression for the input from following, is

I. J0=K0=0
II. J0=K0=1
III. J1=K1=Q0
IV. J1=K1=Q'0
V. J2=K2=Q1Q0
Vl. J2=K2=Q'1Q'0

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