Question
s="a@b@c@d"
a=list(s.partition("@"))
print(a)
b=list(s.split("@",3))
print(b)a.
[‘a’,’b’,’c’,’d’].
[‘a’,’b’,’c’,’d’].
b.
[‘a’,’@’,’b’,’@’,’c’,’@’,’d’].
[‘a’,’b’,’c’,’d’].
c.
[‘a’,’@’,’b@c@d’].
[‘a’,’b’,’c’,’d’].
d.
[‘a’,’@’,’b@c@d’].
[‘a’,’@’,’b’,’@’,’c’,’@’,’d’].
Posted under Python
[‘a’,’b’,’c’,’d’].
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