Question
#include<stdio.h>
int get_min(int a, int b)
{
if(a<b)
return a;
return b;
}
int minimum_time_required(int reach[][3],int spent[][4], int *entry, int *exit, int n)
{
int t1[n], t2[n],i;
t1[0] = entry[0] + spent[0][0];
t2[0] = entry[1] + spent[1][0];
for(i = 1; i < n; i++)
{
t1[i] = get_min(t1[i-1]+spent[0][i], t2[i-1]+reach[1][i-1]+spent[0][i]);
t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+reach[0][i-1]+spent[1][i]);
}
return get_min(t1[n-1]+exit[0], t2[n-1]+exit[1]);
}
int main()
{
int time_to_reach[][3] = {{6, 1, 5},
{2, 4, 7}};
int time_spent[][4] = {{6, 5, 4, 7},
{5, 10, 2, 6}};
int entry_time[2] = {5, 6};
int exit_time[2] = {8, 9};
int num_of_stations = 4;
int ans = minimum_time_required(time_to_reach, time_spent, entry_time, exit_time, num_of_stations);
printf("%d",ans);
return 0;
}
a.
16
b.
18
c.
20
d.
22
Posted under Data Structures and Algorithms
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Q. What is the value stored in t1[2] when the following code is executed?
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