Question

The average residual service time, which again assumes Poisson arrivals as:

a.

Average residual service time= 1/Arithemtic mean+(1+ C^2)

b.

Average residual service time= 2xArithemtic mean+(1+ C^2)

c.

Average residual service time=1/ 2xArithemtic mean+(1+ C^2)

d.

Average residual service time=1/ 2xArithemtic meanx(1+ C^2)

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Answer: (c).Average residual service time=1/ 2xArithemtic mean+(1+ C^2)

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Q. The average residual service time, which again assumes Poisson arrivals as:

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