What is the value of i and j in the below code? #include <stdio.h> int x = 0; int main() { int i = (f() + g()) | g(); //bitwise or int j = g() | (f() + g()); //bitwise or } int f() { if (x == 0) return x + 1; else return x

Question

What is the value of i and j in the below code?

#include <stdio.h>
    int x = 0;
    int main()
    {
        int i = (f() + g()) | g(); //bitwise or
        int j = g() | (f() + g()); //bitwise or
    }
    int f()
    {
        if (x == 0)
            return x + 1;
        else
            return x - 1;
    }
    int g()
    {
        return x++;
    }

i value is 1 and j value is 1

i value is 0 and j value is 0

i value is 1 and j value is undefined

i and j value are undefined

Posted under Data Types,Operators and Expressions in C C Programming

Answer: (c).i value is 1 and j value is undefined

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Q. What is the value of i and j in the below code? #include <stdio.h> int x = 0; int main() { int i = (f() + g()) | g(); //bitwise or int j =...

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Q. What is the value of i and j in the below code? #include <stdio.h> int x = 0; int main() { int i = (f() + g()) | g(); //bitwise or int j =...

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