Question
n = 1;
printf("%d, %dn", 3*n, n++);
a.
Output will be 3, 2
b.
Output will be 3, 1
c.
Output will be 6, 1
d.
Output is compiler dependent
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Q. Comment on the following statement? n = 1; printf("%d, %dn", 3*n, n++);
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