Welcome to the Pointers,Arrays and Structures in C++ MCQs Page
Dive deep into the fascinating world of Pointers,Arrays and Structures in C++ with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Pointers,Arrays and Structures in C++, a crucial aspect of Object Oriented Programming Using C++. In this section, you will encounter a diverse range of MCQs that cover various aspects of Pointers,Arrays and Structures in C++, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Object Oriented Programming Using C++.
Check out the MCQs below to embark on an enriching journey through Pointers,Arrays and Structures in C++. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Object Oriented Programming Using C++.
Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Pointers,Arrays and Structures in C++. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!
Pointers,Arrays and Structures in C++ MCQs | Page 7 of 17
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#include <iostream>
using namespace std;
struct Time
{
int hours;
int minutes;
int seconds;
};
int toSeconds(Time now);
int main()
{
Time t;
t.hours = 5;
t.minutes = 30;
t.seconds = 45;
cout << "Total seconds: " << toSeconds(t) << endl;
return 0;
}
int toSeconds(Time now)
{
return 3600 * now.hours + 60 * now.minutes + now.seconds;
}
#include <iostream>
using namespace std;
int main()
{
struct ShoeType
{
string style;
double price;
};
ShoeType shoe1, shoe2;
shoe1.style = "Adidas";
shoe1.price = 9.99;
cout << shoe1.style << " $ "<< shoe1.price;
shoe2 = shoe1;
shoe2.price = shoe2.price / 9;
cout << shoe2.style << " $ "<< shoe2.price;
return 0;
}
#include <iostream>
using namespace std;
struct sec
{
int a;
char b;
};
int main()
{
struct sec s ={25,50};
struct sec *ps =(struct sec *)&s;
cout << ps->a << ps->b;
return 0;
}
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