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Welcome to the MATLAB Basics MCQs Page

Dive deep into the fascinating world of MATLAB Basics with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of MATLAB Basics, a crucial aspect of MATLAB. In this section, you will encounter a diverse range of MCQs that cover various aspects of MATLAB Basics, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within MATLAB.

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Check out the MCQs below to embark on an enriching journey through MATLAB Basics. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of MATLAB.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of MATLAB Basics. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

MATLAB Basics MCQs | Page 5 of 17

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Q41.
What is the nature of the arrangement of the coefficients to store the following expression in MATLAB? 
y= 3x⁡ + x² + 6

a.

y=[3,0,0,1,0,6]

b.

y=[3,1,6]

c.

y=[3;0;0;1;0;6]

d.

y=[6,0,1,0,0,3]

Discuss
Answer: (a).y=[3,0,0,1,0,6]
Q42.
In the function vpa(β€˜9⁸¹β€™,10), why do we put 9⁸¹ within inverted commas?

a.

We can choose to not put the value within a pair of single inverted comma

b.

We do it so that we don’t get an approximated value

c.

We do it to get the exact value as MATLAB computes exact values, of numerical expressions, when declared within a string

d.

We do it to get a floating-point approximated value, approximated to 14 digits

Discuss
Answer: (c).We do it to get the exact value as MATLAB computes exact values, of numerical expressions, when declared within a string
Q43.
How would you simplify log(x²β°) – log(x¹³) – log(x⁷) in MATLAB? (Assume x is defined as a string variable)

a.

simplify(log(x²β°)-log(x¹³)–log(x⁷));

b.

log(x²β°) – log(x¹³) – log(x⁷)

c.

simplify(log(x²β°)-log(x¹³)–log(x⁷),’IgnoreAnalyticConstraints’,true)

d.

simplify(log(x²β°)-log(x¹³)–log(x⁷))

Discuss
Answer: (c).simplify(log(x²β°)-log(x¹³)–log(x⁷),’IgnoreAnalyticConstraints’,true)
Q44.
What happens if we don’t assign a variable to an expression which evaluates a numerical value?

a.

MATLAB shows error

b.

Nothing happens

c.

The evaluated values are assigned to a variable ans automatically

d.

Depends on the numerical value

Discuss
Answer: (c).The evaluated values are assigned to a variable ans automatically
Q45.
MATLAB sees a ________ ordered variable as a vector of dimension n*1.

a.

nα΅—Κ°, (n+2)α΅—Κ°

b.

nα΅—Κ°, (n+3)α΅—Κ°

c.

(n-1)α΅—Κ°, nα΅—Κ°

d.

nα΅—Κ°, (n-1)α΅—Κ°

Discuss
Answer: (c).(n-1)α΅—Κ°, nα΅—Κ°
Q46.
What will be the output for the below block of code? 
P=[1 3 2]; r=roots(P);

a.

r=[-2,-2]

b.

r=[-2 -1]

c.

There is an error in the code

d.

r = -2
-1

Discuss
Answer: (d). r = -2
-1
Q47.
Name the functions used, for multiplication and division of two polynomials in MATLAB.

a.

conv() and deconv()

b.

mult() and div()

c.

conv() and div()

d.

mult and div

Discuss
Answer: (a).conv() and deconv()
Q48.
How can the formulation of polynomial be done from its roots?

a.

poly(r), r is a row vector, containing the roots of the polynomial

b.

poly([roots as a coloumn vector])

c.

poly([roots as a row vector])

d.

poly([roots in descending order as a coloumn vector])

Discuss
Answer: (b).poly([roots as a coloumn vector])
Q49.
The function to evaluate the value of a polynomial,l for a constant value of the independent variable(say a) in the polynomial is ______

a.

poly(p,a), p is a row vector

b.

polyder(p)

c.

polyint(p)

d.

polyval(c,a), c is a row vector

Discuss
Answer: (d).polyval(c,a), c is a row vector
Q50.
What will be the output when the following code is written in MATLAB? 
u=sin(10);v=pi;whos

a.

u and v are double with 8 bytes

b.

u and v are symbolic objects

c.

error

d.

u and v are double arrays

Discuss
Answer: (a).u and v are double with 8 bytes
Page 5 of 17

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