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Welcome to the Finite Automata and Regular Expression MCQs Page

Dive deep into the fascinating world of Finite Automata and Regular Expression with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Finite Automata and Regular Expression, a crucial aspect of Compiler Design. In this section, you will encounter a diverse range of MCQs that cover various aspects of Finite Automata and Regular Expression, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within Compiler Design.

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Check out the MCQs below to embark on an enriching journey through Finite Automata and Regular Expression. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of Compiler Design.

Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Finite Automata and Regular Expression. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!

Finite Automata and Regular Expression MCQs | Page 2 of 6

Q11.
Which one of the following languages over the alphabet {0, 1} is described by the regular expression: (0+1)*0(0+1)*0(0+1)*?
Discuss
Answer: (c).strings with at least two 0’s
Q12.
Match the following
Group 1 Group 2

P. Regular expression 1. Syntax analysis

Q. Pushdown automata 2. Code generation

R. Dataflow analysis 3. Lexical analysis

S. Register allocation 4. Code optimization
Discuss
Answer: (b).P-3, Q-1, R-4, S-2
Q13.
Let L = L1 ∩ L2, where L1 and L2 are languages as defined below:
L1 = {ambmcanbn | m, n >= 0 }

L2 = {aibjck | i, j, k >= 0 }

Then L is
Discuss
Answer: (c).Context free but not regular
Q14.
Does epsilon ring any change in the automata
Discuss
Answer: (b).No
Q15.
NFA-εs are defined because certain properties can be more easily proved on them as compared to NFA.
Discuss
Answer: (a).True
Q16.
E(q) is known ε-closure of q.
Discuss
Answer: (a).True
Q17.
ε-transitions does not add any extra capacity of recognizing formal
Discuss
Answer: (a).True
Q18.
A nondeterministic finite automaton with ε-moves is an extension of nondeterministic finite automaton
Discuss
Answer: (a).True
Q19.
Is an ordinary NFA and a NFA-ε are equivalent
Discuss
Answer: (a).True
Q20.
Which grammar is not regular
Discuss
Answer: (a).0^n
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