Welcome to the Pointers and Arrays in C MCQs Page
Dive deep into the fascinating world of Pointers and Arrays in C with our comprehensive set of Multiple-Choice Questions (MCQs). This page is dedicated to exploring the fundamental concepts and intricacies of Pointers and Arrays in C, a crucial aspect of C Programming. In this section, you will encounter a diverse range of MCQs that cover various aspects of Pointers and Arrays in C, from the basic principles to advanced topics. Each question is thoughtfully crafted to challenge your knowledge and deepen your understanding of this critical subcategory within C Programming.
Check out the MCQs below to embark on an enriching journey through Pointers and Arrays in C. Test your knowledge, expand your horizons, and solidify your grasp on this vital area of C Programming.
Note: Each MCQ comes with multiple answer choices. Select the most appropriate option and test your understanding of Pointers and Arrays in C. You can click on an option to test your knowledge before viewing the solution for a MCQ. Happy learning!
Pointers and Arrays in C MCQs | Page 4 of 53
Explore more Topics under C Programming
#include <stdio.h>
void m(int p, int q)
{
int temp = p;
p = q;
q = temp;
}
void main()
{
int a = 6, b = 5;
m(a, b);
printf("%d %d\n", a, b);
}#include <stdio.h>
void m(int p, int q)
{
printf("%d %d\n", p, q);
}
void main()
{
int a = 6, b = 5;
m(a);
}#include <stdio.h>
void m(int p)
{
printf("%d\n", p);
}
void main()
{
int a = 6, b = 5;
m(a, b);
printf("%d %d\n", a, b);
}#include <stdio.h>
void main()
{
int a[3] = {1, 2, 3};
int *p = a;
printf("%p\t%p", p, a);
}#include <stdio.h>
void main()
{
char *s = "hello";
char *p = s;
printf("%p\t%p", p, s);
}#include <stdio.h>
void main()
{
char *s= "hello";
char *p = s;
printf("%c\t%c", p[0], s[1]);
}#include <stdio.h>
void main()
{
char *s= "hello";
char *p = s;
printf("%c\t%c", *(p + 3), s[1]);
}#include <stdio.h>
void main()
{
char *s= "hello";
char *p = s;
printf("%c\t%c", 1[p], s[1]);
}#include <stdio.h>
void foo( int[] );
int main()
{
int ary[4] = {1, 2, 3, 4};
foo(ary);
printf("%d ", ary[0]);
}
void foo(int p[4])
{
int i = 10;
p = &i;
printf("%d ", p[0]);
}#include <stdio.h>
int main()
{
int ary[4] = {1, 2, 3, 4};
int *p = ary + 3;
printf("%d\n", p[-2]);
}Suggested Topics
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