adplus-dvertising
frame-decoration

Question

What is the output of the following code?
ztrans('[1 0 1 0 1]',z)

a.

[ z/(z – 1), 0, z/(z – 1), 0, z/(z – 1)]

b.

[ z/(z + 1), 0, z/(z – 1), 0, z/(z – 1)]

c.

[ z/(z – 1), 0, z/(z – 1), 0, z/(z -+1)]

d.

[ z/(z + 1), 0, z/(z – 1), 0, z/(z + 1)]

Answer: (a).[ z/(z – 1), 0, z/(z – 1), 0, z/(z – 1)]

Engage with the Community - Add Your Comment

Confused About the Answer? Ask for Details Here.

Know the Explanation? Add it Here.

Q. What is the output of the following code?