Question
x = m;
y = 1;
while (x - y > e)
{
x = (x + y)/2;
y = m/x;
}
print(x);
(Assume m > 1, e > 0).
a.
log m
b.
m^2
c.
m^1/2
d.
m^1/3
Posted under GATE cse question paper Data Structures and Algorithms
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Q. What does the following algorithm approximate? x = m; y = 1; while (x - y > e) { x = (x + y)/2; y = m/x; } print(x); (Assume m...
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