adplus-dvertising
frame-decoration

Question

The grammar is not SLR (1) because it is having?

a.

Shift reduce conflict

b.

Reduce-Reduce conflict

c.

Both a and b

d.

None of these

Answer: (a).Shift reduce conflict

Engage with the Community - Add Your Comment

Confused About the Answer? Ask for Details Here.

Know the Explanation? Add it Here.

Q. The grammar is not SLR (1) because it is having?

Similar Questions

Discover Related MCQs

Q. What is E val for string 1 * 0?

Q. Consider the following grammar:

Stmt → if expr then stmt else stmt | if expr then stmt

After removing left factoring the resulting grammar will be?

Q. Consider the following grammar:

A → cAd A → ab/ac/a

For Input string cad, how many times the recursive descent parser will backtrack ?

Q. Consider the following grammar:

S → Abc A → ab/ac/a

For Input string cad, how many times the recursive descent parser will backtrack?

Q. Consider the following grammar:

num → 10 ⁄ 1000 ⁄ numo ⁄ num num

Which of the following statement correctly represent the grammar?

Q. Consider the following grammar:

S → S+S
S → S*S
S → id

What we can say about precedence of operator + and * ?

Q. Suppose ↑ is a binary operation and consider the following:

E → T↑E⁄T
T → id

Which of the following statement is true?

Q. Consider the following simple context-free grammar:

S → Aa ⁄ bAc ⁄ dc ⁄ bda

Determine true (T), false (F) of the following statements:
i) The grammar is SLR (1)
ii) The grammar is LR (1)
iii) The grammar is LALR (1)?

Q. In some phase of a compiler:

Input:
temp1: = int to real (60)
temp2: = id3 * temp1
temp3: = id2 * temp2
id1: = temp3

Output:
temp1: = id3 * 60.0
id1: = id2 + temp1

Where temp1, temp2, temp3 are temporary storage id1, id2, id3 are identifiers. “int to real” is converting int 60 to a real number. The above phase is

Q. Consider the grammar:

S → ab/ac

Which of the following is true?

Q. How many bits are in the “tag” filed in the cache?