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Question

In propositional logic P ⇔ Q is equivalent to (Where ~ denotes NOT):

a.

~ (P ˅ Q) ˄ ~ (Q ˅ P)

b.

(~ P ˅ Q) ˄ (~ Q ˅ P)

c.

(P ˅ Q) ˄ (Q ˅ P)

d.

~ (P ˅ Q) → ~ (Q ˅ P)

Answer: (b).(~ P ˅ Q) ˄ (~ Q ˅ P)

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Q. In propositional logic P ⇔ Q is equivalent to (Where ~ denotes NOT):