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Question

If Sₙ=4Sₙ₋₁+12n, where S₀=6 and S₁=7, find the solution for the recurrence relation.

a.

aₙ=7(2ⁿ)−29/6n6ⁿ

b.

aₙ=6(6ⁿ)+6/7n6ⁿ

c.

aₙ=6(3ⁿ⁺¹)−5n

d.

aₙ=nn−2/6n6ⁿ

Answer: (b).aₙ=6(6ⁿ)+6/7n6ⁿ

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Q. If Sₙ=4Sₙ₋₁+12n, where S₀=6 and S₁=7, find the solution for the recurrence relation.

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