Question
a.
∀nP ((n) → Q(n))
b.
∃ nP ((n) → Q(n))
c.
∀n~(P ((n)) → Q(n))
d.
∀nP ((n) → ~(Q(n)))
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Q. Let the statement be “If n is not an odd integer then square of n is not odd.”, then if P(n) is “n is an not an odd integer” and Q(n) is “(square of n) is not odd.” For direct...
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