Question
S → aB | bA
A → a | as | bAA
B → b | bs | aBB
will generate
a.
odd numbers of a's and odd numbers of b's
b.
even numbers of a's and even numbers of b's
c.
equal numbers of a's and b's
d.
different numbers of a's and b's
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Q. The following Context-Free Grammar (CFG) : S → aB | bA A → a | as | bAA B → b | bs | aBB will generate
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