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Question

What is the correct syntax of open() function?

a.

file = open(file_name [, access_mode][, buffering])

b.

file object = open(file_name [, access_mode][, buffering])

c.

file object = open(file_name)

d.

none of the mentioned

Posted under Python

Answer: (b).file object = open(file_name [, access_mode][, buffering])

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Q. What is the correct syntax of open() function?