Question
def foo(i, x=[]):
x.append(x.append(i))
return x
for i in range(3):
y = foo(i)
print(y)
a.
[[[0]], [[[0]], [1]], [[[0]], [[[0]], [1]], [2]]].
b.
[[0], [[0], 1], [[0], [[0], 1], 2]].
c.
[0, None, 1, None, 2, None].
d.
[[[0]], [[[0]], [1]], [[[0]], [[[0]], [1]], [2]]].
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