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Question

What is the output of the code shown below?
l=["good", "oh!", "excellent!", "#450"]
[n for n in l if n.isalpha() or n.isdigit()]

a.

[‘good’, ‘oh’, ‘excellent’, ‘450’ ]

b.

[‘good’]

c.

[‘good’, ‘#450’]

d.

[‘oh!’, ‘excellent!’, ‘#450’]

Posted under Python

Answer: (b).[‘good’]

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