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Question

What is the output of the following code?
#include<stdio.h>
#include<stdlib.h>
struct Node
{
     int val;
     struct Node* next;
}*head;
int linear_search(int value)
{
      struct Node *temp = head->next;
      while(temp -> next != 0)
      {
            if(temp->val == value)
            return 1;
            temp = temp->next;
      }
      return 0;
}
int main()
{
     int arr[6] = {1,2,3,4,5,6};
     int n = 6,i;
     head = (struct Node*)malloc(sizeof(struct Node));
     head->next = 0;
     struct Node *temp;
     temp = head;
     for(i=0; i<n; i++)
     {
           struct Node *newNode = (struct Node*)malloc(sizeof(struct Node));
           newNode->next = 0;
           newNode->val = arr[i];
           temp->next = newNode;
           temp = temp->next;
     }
     int ans = linear_search(60);
     if(ans == 1)
       printf("Found");
     else
       printf("Not found");
     return 0;
}

a.

Found

b.

Not found

c.

Compile time error

d.

Runtime error

Answer: (b).Not found

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Q. What is the output of the following code?

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