Question
a)
public int pop()
{
int res=-999,count=0;
if(q1.size()>0)
{
count = q1.size();
while(count>0)
q2.offer(q1.poll());
res = q1.poll();
}
if(q2.size()>0)
{
count = q2.size();
while(count>0)
q1.offer(q2.poll());
res = q2.poll();
}
return res;
}
b)
public int pop()
{
int res=-999,count=0;
if(q1.size()>0)
{
count = q1.size();
while(count>1)
q2.offer(q1.poll());
res = q2.poll();
}
if(q2.size()>0)
{
count = q2.size();
while(count>1)
q1.offer(q2.poll());
res = q1.poll();
}
return res;
}
c)
public int pop()
{
int res=-999,count=0;
if(q1.size()>0)
{
count = q1.size();
while(count>1)
q2.offer(q1.poll());
res = q1.poll();
}
if(q2.size()>0)
{
count = q2.size();
while(count>1)
q1.offer(q2.poll());
res = q2.poll();
}
return res;
}
d) None of the mentioneda.
a
b.
b
c.
c
d.
d
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Q. Making the pop operation costly, select the code snippet which implements the same.
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