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Question

How does compiler convert “::operator new” implicitly?

a.

::operator new( sizeof( type ) )

b.

::operator new( sizeof( ) )

c.

new operator :: type sizeof( type )

d.

new sizeof( type ) operator

Posted under Object Oriented Programming

Answer: (a).::operator new( sizeof( type ) )

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Q. How does compiler convert “::operator new” implicitly?
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