Question
a.
54
b.
43
c.
5
d.
24
Posted under Cryptography and Network Security
Engage with the Community - Add Your Comment
Confused About the Answer? Ask for Details Here.
Know the Explanation? Add it Here.
Q. For p = 11 and q = 19 and choose d=17. Apply RSA algorithm where Cipher message=80 and thus find the plain text.
Similar Questions
Discover Related MCQs
Q. For p = 11 and q = 19 and choose e=17. Apply RSA algorithm where message=5 and find the cipher text.
View solution
Q. In RSA, we select a value ‘e’ such that it lies between 0 and Ф(n) and it is relatively prime to Ф(n).
View solution
Q. In RSA, Ф(n) = _______ in terms of p and q.
View solution
Q. In the RSA algorithm, we select 2 random large values ‘p’ and ‘q’. Which of the following is the property of ‘p’ and ‘q’?
View solution
Q. RSA is also a stream cipher like Merkel-Hellman.
View solution
Q. Suppose that plaintext message units are single letters in the usual 26-letter alphabet with A-Z corresponding to 0-25. You receive the sequence of ciphertext message units 14, 25, 89. The public key is the sequence {57, 14, 3, 24, 8} and the secret key is b = 23, m = 61.
Decipher the message. The Plain text is
View solution
Q. Find the ciphertext for the message {100110101011011} using superincreasing sequence { 1, 3, 5, 11, 35 } and private keys a = 5 and m=37.
View solution
Q. Compute private key (d, p, q) given public key (e=23, n=233 ´ 241=56,153).
View solution
Q. In an RSA system the public key of a given user is e = 31, n = 3599. What is the private key of this user?
View solution
Q. For p = 11 and q = 17 and choose e=7. Apply RSA algorithm where Cipher message=11 and thus find the plain text.
View solution
Q. For p = 11 and q = 17 and choose e=7. Apply RSA algorithm where PT message=88 and thus find the CT.
View solution
Q. The plaintext message consist of single letters with 5-bit numerical equivalents from (00000)2 to (11001)2. The secret deciphering key is the superincreasing 5-tuple (2, 3, 7, 15, 31), m = 61 and a = 17. Find the ciphertext for the message “WHY”.
View solution
Q. In Merkle-Hellman Cryptosystem, the public key can be used to decrypt messages, but cannot be used to decrypt messages. The private key encrypts the messages.
View solution
Q. In Merkle-Hellman Cryptosystem, the hard knapsack becomes the private key and the easy knapsack becomes the public key.
View solution
Q. Another name for Merkle-Hellman Cryptosystem is
View solution
Q. Consider knapsack that weighs 23 that has been made from the weights of the superincreasing series {1, 2, 4, 9, 20, and 38}. Find the ‘n’.
View solution
Q. A superincreasing knapsack problem is ____ to solve than a jumbled knapsack.
View solution
Q. Set {1, 2, 3, 9, 10, and 24} is superincreasing.
View solution
Q. For the Knapsack: {1 6 8 15 24}, find the plain text code if the ciphertext is 38.
View solution
Q. For the Knapsack: {1 6 8 15 24}, Find the cipher text value for the plain text 10011.
View solution
Suggested Topics
Are you eager to expand your knowledge beyond Cryptography and Network Security? We've curated a selection of related categories that you might find intriguing.
Click on the categories below to discover a wealth of MCQs and enrich your understanding of Computer Science. Happy exploring!