Q. Which Cryptographic system uses C1 = (e1^r) mod p and C1 = (e2^r x P) mod p at the encryption side?

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Q. Sender chooses p = 107, e1 = 2, d = 67, and the random integer is r=45. Find the plaintext to be transmitted if the ciphertext is (28,9).

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Q. In Elgamal cryptosystem, given the prime p=31. Choose e1= first primitive root of p and d=10, calculate e2.

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Q. In Elgamal cryptosystem, given the prime p=31. Encrypt the message “HELLO”; use 00 to 25 for encoding. The value of C2 for character ‘L’ is

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Q. In Elgamal cryptosystem, given the prime p=31. Encrypt the message “HELLO”; use 00 to 25 for encoding. The value of C2 for character ‘O’ is

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Q. In Elgamal cryptosystem, given the prime p=31. What is the respective plaintext character for C = (27, 20)?

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Q. Imagine you had a set of weights {62, 93, 26, 52, 166, 48, 91, and 141}. Find subset that sums to V = 302.

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Q. For the Knapsack: {1 6 8 15 24}, Find the cipher text value for the plain text 10011.

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Q. For the Knapsack: {1 6 8 15 24}, find the plain text code if the ciphertext is 38.

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Q. Set {1, 2, 3, 9, 10, and 24} is superincreasing.

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Q. A superincreasing knapsack problem is ____ to solve than a jumbled knapsack.

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Q. Consider knapsack that weighs 23 that has been made from the weights of the superincreasing series {1, 2, 4, 9, 20, and 38}. Find the ‘n’.

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Q. Another name for Merkle-Hellman Cryptosystem is

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Q. In Merkle-Hellman Cryptosystem, the hard knapsack becomes the private key and the easy knapsack becomes the public key.

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Q. In Merkle-Hellman Cryptosystem, the public key can be used to decrypt messages, but cannot be used to decrypt messages. The private key encrypts the messages.

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Q. The plaintext message consist of single letters with 5-bit numerical equivalents from (00000)2 to (11001)2. The secret deciphering key is the superincreasing 5-tuple (2, 3, 7, 15, 31), m = 61 and a = 17. Find the ciphertext for the message “WHY”.

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Q. For p = 11 and q = 17 and choose e=7. Apply RSA algorithm where PT message=88 and thus find the CT.

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Q. For p = 11 and q = 17 and choose e=7. Apply RSA algorithm where Cipher message=11 and thus find the plain text.

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Q. In an RSA system the public key of a given user is e = 31, n = 3599. What is the private key of this user?

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Q. Compute private key (d, p, q) given public key (e=23, n=233 ´ 241=56,153).

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