Question
#include <stdio.h>
void fun(char**);
int main()
{
char *argv[] = {"ab", "cd", "ef", "gh"};
fun(argv);
return 0;
}
void fun(char **p)
{
char *t;
t = (p+= sizeof(int))[-1];
printf("%s\n", t);
}a.
ab
b.
cd
c.
ef
d.
gh
Posted under Functions C Programming
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Q. If int is 2 bytes wide.What will be the output of the program?
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