Question
Process A
int Y;
A1: Y = X*2;
A2: X = Y;
signal(T);
Process B
int Z;
B1: wait(T);
B2: Z = X+1;
X = Z;
T is set to 0 before either process begins execution and, as before, X is set to 5.
Now, how many different values of X are possible after both processes finish executing ?
a.
one
b.
two
c.
three
d.
four
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Q. The program follows to use a shared binary semaphore T : Process A int Y; A1: Y = X*2; A2: X = Y; signal(T); Process B int Z; B1:...
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