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Question

What is the output of this C code (run without any command line arguments)?
#include <stdio.h>
    int main(int argc, char *argv[])
    {
        while (*argv  !=  NULL)
        printf("%s\n", *(argv++));
        return 0;
    }

a.

Segmentation fault/code crash

b.

Executable file name

c.

Depends on the platform

d.

Depends on the compiler

Posted under C Programming

Answer: (b).Executable file name

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Q. What is the output of this C code (run without any command line arguments)? #include <stdio.h> int main(int argc, char *argv[]) { while (*argv !=...

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