Question
#include <stdio.h>
int main(int argc, char *argv[])
{
while (*argv++ != NULL)
printf("%s\n", *argv);
return 0;
}a.
Segmentation fault/code crash
b.
Executable file name
c.
Depends on the platform
d.
Depends on the compiler
Posted under Pointers and Arrays in C C Programming
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Q. What is the output of this C code (run without any commandline arguments)? #include <stdio.h> int main(int argc, char *argv[]) { while (*argv++ != NULL)...
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